The Astronomical Unit
Stellar Magnitudes
Other Units and Conventions
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A natural starting point for astronomical distances is the average distance from the Earth to the Sun. As planets move in ellipses around the sun, the average distance is taken to be the semi-major axis of the earth's orbit. This distance is called the astronomical unit (AU) and is equal to 1.496 x 1011m. However the unit is only appropriate on interplanetary scales as the distances to other stars are so great as to render it too small a unit to be useful. The table shows the relative distances of the planets in AU. |
| Planet | Mean Distance (semi-major axis)/A |
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Suppose we record the position of a nearby star at two points on the earth's orbit separated by a time interval of six months (note that these positions are also separated by a distance of 2 AU). Therefore the parsec (the word is an abbreviation of parallax and arc second) is equal to 206,264.81 AU. |
The Light Year (ly)
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This is the distance that a photon of light would travel in one year. Since light travels at 3 x 108m s-1 we can calculate this as 9.46 x 1015m. |
PARSECS AND LIGHT YEARS
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When you look up at the stars at night, it is obvious that some are brighter than others. However this is deceptive since the observed brightness of an object clearly depends on how far away you are from it. |
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and represents the light flux received. |
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Astrophysicists prefer to talk about a star's brightness rather than its luminosity and this is expressed as a scale of magnitudes. The magnitude scale on which stars are rated is based on a convention first devised by Hipparchus. They are classified by apparent magnitude, rating the brightest stars that can be seen with the naked eye as magnitude 1.0 and the faintest as magnitude 6.0. Later, with the invention of the telescope and for consistency, it became neccessary to assign to some stars a magnitude brighter than 1.0. Hence Vega has magnitude 0 and Sirius magnitude -1.4 whereas the sun has a magnitude of -26.74. It is important to understand that the more negative the value of apparent magnitude, the brighter the star appears. Conversely, the larger the magnitude (more positive) the fainter the star appears. |
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In 1856, an English astronomer, Norman Pogson, formulated Hipparchus's somewhat subjective scale into a precise mathematical law expressed as: |
Absolute Magnitudes
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Now suppose you could place all the stars at a fixed distance from the earth. The differing distances would not then be a factor in how bright the stars appeared. Instead, the differences in magnitude would only be due to differences in luminosities and these values would be absolute. |
Bolometric Magnitudes
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Allowances have to be made for the fact that some stars may emit a significant amount of their light in the non-visible part of the electromagnetic spectrum. For example, very luminous hot stars of appear dim to the eye only because they emit most of their radiation in the ultraviolet and, in addition, the earth's atmosphere absorbs many non-visible wavelengths. It can be seen then that absolute magnitudes as deduced from apparent magnitudes using the distance magnitude relation need to be corrected for these effects. |
Luminosity and Bolometric Magnitude
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Luminosities are normally expressed in terms of the sun's luminosity Lo. For two stars 1 & 2 situated at the same distance d, the ratio of their brightness is equal to the ratio of their luminosities. Now suppose we let star 1 be the sun, it can be shown that... |
SCALE OF MAGNITUDES
BOLOMETER
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Astronomers and astrophysicists generally use the SI system of units however some measurements are expressed in multiples relative to the sun so that the values... |
KARL JANSKY
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